the price of 3 chairs and 2 table is 4500 rupees and price of 5 chairs and 3 table is 7000 Rupees then find the price of 2 chairs and 2 tables
Answers
let price of 1 table = y
3x + 2y = 4500...................equation 1
5x + 3y = 7000.....................equation 2
multiplying eq.1 by 3 and eq 2 by 2 we get
9x + 6y = 13500.......eq 3
10x+6y= 14000..........eq4 (subtracting eq3 and eq4 we get) - - -
- x = -500
x=500
y=1500
cost of 2 chairs = 2*500=1000
costr of 2 tables = 2*1500=3000
Answer:
The total price of two chairs and two tables is rupees 4000.
Step-by-step explanation:
3x + 2y = 4500 ... (1)
From the second condition,
5x + 3y = 7000 ... (2)
Multiplying equation (1) by 3 and equation (2) by 2,
9x + 6y = 13500 ... (3)
10x + 6y = 14000 ... (4)
Subtracting equation (3) from equation (4),
(10x + 6y = 14000)
-(9x + 6y = 13500)
——————————
x + 0 = 500
=> 2x = 2 × 500 = 1000 ... (5)
Substituting x = 599 in equation (1)
3(500) + 2y = 4500
=> 1500 + 2y = 4500
=> 2y = 4500 - 1500
=> 2y = 3000 ... (6)
Now, the price of 2 chairs and 2 tables is
Rupees(1000 + 3000) [From (5) and (6)]
= rupees 4000
Hence, the total price of 2 chairs and 2 tables is rupees 4000.
Hope it helps :)