The price of 3 chairs and 2 tables is 4500 rupees and price of 5 chairs and 3 tables is 7000 rupees, then find the total price of 2 chairs and 2 tables. 90
Answers
Let the Price of a Chair be Rs x
Let the Price of a Chair be Rs x Let the price of a Table be Rs y
The price of 33 chairs and 22 tables is 4500 RS
⇒3x+2y=4500 ____ (1)
price of 55 chairs and 33 tables is 7000Rs, ⇒5x+3y=7000 ______(2)
price of 55 chairs and 33 tables is 7000Rs, ⇒5x+3y=7000 ______(2) Solving Equation 1 and 2 ,we get-
price of 55 chairs and 33 tables is 7000Rs, ⇒5x+3y=7000 ______(2) Solving Equation 1 and 2 ,we get- ∴ x=500 & y=1500
⇒ Price of 2 Chairs and 2 Tables =2x+2y
⇒ Price of 2 Chairs and 2 Tables =2x+2y =2(x+y)
⇒ Price of 2 Chairs and 2 Tables =2x+2y =2(x+y) =2(500+1500)
⇒ Price of 2 Chairs and 2 Tables =2x+2y =2(x+y) =2(500+1500) =2×2000
⇒ Price of 2 Chairs and 2 Tables =2x+2y =2(x+y) =2(500+1500) =2×2000 = Rs. 4000
⇒ Price of 2 Chairs and 2 Tables =2x+2y =2(x+y) =2(500+1500) =2×2000 = Rs. 4000Therefore ,Cost of 2 Chairs and 2 Tables is 4000 RS.