Question

The price of 3 chairs and 2 tables is 4500rupees and the price of 5 chairs and 3 tables is

7000 rupees, then find the price of 4 chairs and 4 tables.​

Answer 1

★Given:-

• The price of 3 chairs and 2 tables is 4500rupees.
• The price of 5 chairs and 3 tables is  7000 rupees.

★To find:-

• Price of 4 chairs & 4 tables.

★Solution:-

Let the price of 1 chair be x

And the price of 1 table be y

Then,

• Price of 3 chairs = 3x
• Price of 2 tables = 2y
• Price of 5 chairs = 5x
• Price of 3 tables = 3y

Given that the price of 3 chairs and 2 tables is 4500

Therefore,

➜3x+2y=4500-----(1)

Also given that,The price of 5 chairs and 3 tables is 7000

Therefore,

➜5x+3y=7000-----(2)

Multiplying equation(1) with 3,

• 9x+6y=13500---(3)

Multiplying equation(2) with 2,

• 10x+6y=14000---(4)

Now subtracting equation(4) from (3),

9x+6y=13500

10x+6y=14000

−    −      −        

    −x=−500    

➜x = 500

Substituting values of x in equation(1),

➜3x+2y = 4500

➜3(500)+2y = 4500

➜2y = 4500 - 1500

➜2y = 3000

➜y = 3000/2

➜y = 1500

We know,

• Price of 4 chairs = 4x
• Price of 4 tables = 4y

Hence,

Price of 4 chairs and 4 tables will be:

➜4x + 4y

Substituting the values of x&y,

➜4(500)+4(1500)

➜4(500+1500)

➜4(2000)

➜Rs.8000

Hence,

The price of 4 chairs and 4 tables are Rs.8000.

_______________

Answer 2

Question:

The price of 3 chairs and 2 tables is 4500rupees and the price of 5 chairs and 3 tables is 7000 rupees, then find the price of 4 chairs and 4 tables.

Given:

The price of 3 chairs and 2 tables is 4500rupees.

The price of 5 chairs and 3 tables is  7000 rupees.

To find:

Price of 4 chairs & 4 tables.

Answer:

Rs.8000

$\huge\red{\mid{\underline{\overline{\textbf{Solution\:࿐}}}\mid}}$

Step-by-step explanation:

Let the price of 1 chair be x

And the price of 1 table be y

Then,

Price of 3 chairs = 3x

Price of 2 tables = 2y

Price of 5 chairs = 5x

Price of 3 tables = 3y

Given that the price of 3 chairs and 2 tables is 4500

Therefore,

3x+2y=4500-----(1)

Also given that,The price of 5 chairs and 3 tables is 7000

Therefore,

5x+3y=7000-----(2)

Multiplying equation(1) with 3,

9x+6y=13500---(3)

Multiplying equation(2) with 2,

10x+6y=14000---(4)

Now subtracting equation(4) from (3),

9x+6y=13500

10x+6y=14000

−    −      −        

    −x=−500    

x = 500

Substituting values of x in equation(1),

➪3x+2y = 4500

➪3(500)+2y = 4500

➪2y = 4500 - 1500

➪2y = 3000

➪y = 3000/2

➪y = 1500

As we know"

Price of 4 chairs = 4x

Price of 4 tables = 4y

Price of 4 chairs and 4 tables will be:

4x + 4y

Substituting the values of x and y.

4(500)+4(1500)

4(500+1500)

4(2000)

Rs.8000

.'.

The price of 4 chairs and 4 tables are

$\bold{\huge{\fbox{\color{maroon}{Rs.8000}}}}$

$\sf\red{hope\:it\:helps\:you}$