Math, asked by devathrajneeraj9, 6 hours ago

The price of 3 chairs and 2 tables is Rs.1300. If a table costs Rs.50 more than a chair, then find the cost of a chair​

Answers

Answered by lohitpatil16
1

Answer: 100 rupees

Step-by-step explanation:

Let consider chair as x and table as y

According to the question

2x + 3y = ₹ 1300…..eq 1

3x +2y = ₹ 1200……eq 2

Multiply eq 1 by 3 and eq 2 by 2

6x + 9y = ₹3900

6x + 4y = ₹2400

Now subtract eq 2 from eq 1, we get

5y = ₹1500

Y = ₹300

Now put the value in eq 2

6x +4×300 =₹ 2400

6x +1200 =₹ 2400

6x = ₹ (2400–1200)

6x = ₹1200

X = ₹ 200

Chair price = x = ₹200

Table price = y = ₹300

Cost of each table is more than that of chair = ₹(300–200) = ₹100 Ans…

Answered by manastiwari4130
1

Answer:

please mark me as brainlist here is your answer

Step-by-step explanation:

The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?

Let consider chair as x and table as y

According to the question

2x + 3y = ₹ 1300…..eq 1

3x +2y = ₹ 1200……eq 2

Multiply eq 1 by 3 and eq 2 by 2

6x + 9y = ₹3900

6x + 4y = ₹2400

Now subtract eq 2 from eq 1, we get

5y = ₹1500

Y = ₹300

Now put the value in eq 2

6x +4×300 =₹ 2400

6x +1200 =₹ 2400

6x = ₹ (2400–1200)

6x = ₹1200

X = ₹ 200

Chair price = x = ₹200

Table price = y = ₹300

Cost of each table is more than that of chair = ₹(300–200) = ₹100 Ans…

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