Question

the price of 3 notebooks and 2 test books is rupees is 135 but a notebook cost rupees 5 more than the test book. Find the cost of both the network and testbook

Answer 1

let us take the cost of a notebook be'x'
let us take the cost of one testbook be 'y'

according to the question,
3 notebook and 2 testbook is of 135 rupees
so, 3x+2y=135.......(1)
a notebook cost 5 rupees more than the testbook
so, x=y+5
x-y=5.........(2)
multiply both sides by 3 in equation
3(x-y)=(3)(5)
3x-3y=15......(3)

subtract equation (1) and (3)
3x+2y-(3x-3y)=135-15
3x+2y-3x+3y=120
5y=120
y=120/5
y=24
put the value of y in eq. 2

x-y=5
x-24=5
x=5+24
x=29

Answer 2

Let cost of 1 tb =x
Let cost of 1 nb=x+5
135=3 nb+2 tb
135=3(x+5)+ 2(x)
x=24
Tb=24rs
Nb=29rs