Question

the price of 4 tables and 6 chairs is ₹680 but a table cost ₹20 more than a chair. find price if each. ​

Answer 1

Step-by-step explanation:

let price of table = x

and price of chair = y

According to questions first condition

4x+6y = 680 --------(i)

According to questions second condition

x+20 = y

therefore, x-y= -20 ------(ii)

equation (ii) multiply by 4

4x-4y=-80 -------(iii)

subtract equation (iii) from (i)

4x +6y =680

4x-4y =-80

- +. +

__________

0 +10y = 760

therefore ,y= 760/10

y =76 put in equation (ii)

x-76 = -20

x= -20+76

x= 57

Hence the price of table =₹57

and the price of chair = ₹76