The price of 9 pencils and 12 pens is₹279 and that of 8 pencils and 16 pens is ₹312.Then sum of the cost of one pen and a pencil is
Answers
Step-by-step explanation:
Given :-
The price of 9 pencils and 12 pens is₹279 and that of 8 pencils and 16 pens is ₹312.
To find :-
Find the sum of the cost of one pen and a pencil?
Solution :-
Let the cost of one pencil be ₹ X
Let the cost of one pen be ₹ Y
Given that
The price of 9 pencils and 12 pens = ₹ 279
=> 9X+12 Y = 279
=> 3(3X+4Y) = 279
=> 3X+4Y = 279/3
=> 3X+4Y = 93 --------------(1)
And
The cost of 8 pencils and 16 pens = ₹ 312
=> 8X +16Y = 312
=> 8(X+2Y) = 312
=> X+2Y = 312/8
=>X+2Y = 39 ---------------(2)
=> X = 39-2Y -------------(3)
On Substituting the value of X in (1) then
3X+4Y = 93
=> 3(39-2Y) +4Y = 93
=> 117-6Y+4Y = 93
=> 117-2Y = 93
=> -2Y = 93-117
=> -2Y = -24
=> Y = -24/-2
=> Y = 12
On Substituting the value of Y in (3)
=> X = 39-2(12)
=> X = 39-24
=> X = 15
Therefore X = 15 and Y = 12
The cost of one pencil =₹15
The cost of one pen = ₹ 12
Now ,
The sum of the cost of one pencil and the cost of one pen
=> 15+12
= ₹ 27
Answer:-
The sum of the cost of one pencil and the cost of one pen = ₹ 27
Check:-
The cost of one pencil =₹15
The cost of one pen = ₹ 12
The price of 9 pencils and 12 pens
=> 9(15)+12(12)
=> 135+144
= 279
and
The cost of 8 pencils and 16 pens
=> 8(15)+16(12)
=> 120+192
=> 312
Verified the given relations in the given problem.
Used Method :-
- Substitution method
Given:-
- The price of 9 pencils and 12 pens is₹279 and that of 8 pencils and 16 pens is ₹312.
To Find:-
- Sum of the cost of one pen and a pencil.
Method Used:-
- Substitution Method
Solution:-
Let the cost of 1 pencil be x and the cost of 1 pen be y.
According to question,
____{1}
Also,
____{2}
Subtracting {2} from {3},
⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀
⠀⠀⠀ (–)⠀ ⠀(–)⠀ ⠀(–)
⠀⠀⠀⠀━━━━━━━━
⠀⠀⠀⠀⠀⠀⠀
Putting Value of x in {1},
The value of x and y is 15 and 12 respectively.
- Cost of 1 pencil = x = ₹15
- Cost of 1 pen = y = ₹12
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