Question

The price of a car increased by 15% in a year. next year price increases with the same rate. if the price at the start of third year is Rs 132250 then the price at the start of first year was? answers a) 100000 b) 110000 c) 210000 d) 250000​

Answer 1

Price at the start of first year is Rs.

I ooooo

Answer 2

Answer:

Step-by-step explanation:

Let the 1st year Price = x

Let the Percentage of 1st-year increase by 15% on x  simply it will become 115 because every value is 100% of itself.

Now

2nd year Price = 115% of x

Let the Percentage of 2nd-year increase by 15% on 115%.

Increase of 15% on 115%

115×15=1725 Divide it by 100 1725/100=17.25%

Adding 17.25 to the 2nd-year Percentage
Add 17.25 into 2nd Year Percentage it will become 132.25%

3rd-year Price = 132.25% of x

We know the Price for 3rd year which is Rs 132250.

Solve

1st-year price

132250=132.25% of x

132250=$\frac{132.25}{100}$×(x)

$\frac{132250 *100}{132.25}$=x

10000=x

2nd-year price

15% of 100000 = 2nd-year price

115000= 2nd year price

Conclusion

The price for 1st year was Rs. 100000

The price for the 2nd year was  Rs.115000