Math, asked by pradiptripathy2900, 1 year ago

the price of a car is lowered by 20 person to rupees 40000 what was the original price also find the radiation in price

Answers

Answered by Hiteshbehera74
2

Initial price = x

Final price = ₹40000

Change in percentage = -20%


Change in percentage = [(Final-Initial)/(Initial)] x 100


-20 = (40000-x/x)100

-0.2x = 40000-x

-0.2x+x = 40000

0.8x = 40000

x = 40000/0.8

x = 50000


Therefore, the original price of the car was ₹50,000.




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