Math, asked by brain8042, 10 months ago

The price of a climbing trip to Mount Kilimanjaro includes an initial fee plus a constant fee per meter. The table compares the total distance of a trip (in meters) and the price of the trip (in dollars). Distance (meters) Price (dollars) 707070 114.1114.1114, point, 1 100100100 118118118 130130130 121.90121.90121, point, 90 How far can you climb for \$131$131dollar sign, 131?

Answers

Answered by bhagyashreechowdhury
7

Given:

The price of a climbing trip to Mount Kilimanjaro includes an initial fee plus a constant fee per meter.

Table:

Distance (meters)          Price (dollars)

    70                                    114.1

   100                                    118

    130                                    121.90

To find:

Meters that can be climbed for $ 131

Solution:

Finding the price of climbing the trip of 1 m:

From the given table we can see that

The common difference in the distance in meters or the increase in distance is 30 m ..... [100 - 70 = 30 m & 130 - 100 = 30 m]

Also, the increase in the price in dollars is → 118 - 114.1 =  $ 3.9 & 121.90 - 100 = $ 3.9

So, we get, the price of climbing a trip of 30 m = $3.9

The price of climbing a trip of 1 m = \frac{3.9}{30} = $ 0.13initial fee for climbing every meter

Finding the initial fee & the constant fee per meter:

(i) Taking the distance = 70 m and total price = $ 114.1

∴ The initial price of climbing 70 m = $0.13 * 70 = $ 9.1

∴ The constant fee per meter = $ 114.1 - $ 9.1 = $ 105

(ii) Taking the distance = 100 m and total price = $ 118

∴ The initial price of climbing 100 m = $0.13 * 100 = $ 13

∴ The constant fee per meter = $ 118 - $ 13 = $ 105

(iii) Taking the distance = 130 m and total price = $ 121.90

∴ The initial price of climbing 130 m = $0.13 * 130 = $ 16.9

∴ The constant fee per meter = $ 121.90 - $ 16.9 = $ 105

From the above calculation we can form a linear equation as:

\boxed{x = 0.13y + 105}

where

x = total price of a climbing trip

y = distance covered in a climbing trip

Finding the distance covered with a price of the climbing trip of $ 131:

here we have x = $131 and by substituting the value of x in the linear equation we will find the value of y

131 = 0.13x +105

⇒ 0.13x = 131 - 105

⇒ 0.13x = 26

⇒ x = \frac{26}{0.13}

x = 200 m

Thus, we can climb a trip of 200 m to Mount Kilimanjaro for $131.

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