the price of a coil depends upon the product of its thickness and the square of the diameter. The ratio of thickness of two coins is 8:9. if the value of the second coin is double of the first coin then what will be the ratio of their diameters?
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Answer:
Let the diameters and thickness of the two coins be d
1
,t
1
and d
2
,t
2
respectively then
Given,
v
2
v
1
=
d
2
2
d
1
2
×
t
2
t
1
⇒
1
4
=
3
2
4
2
×
t
2
t
1
⇒
4
9
=
t
2
t
1
∴
t
2
t
1
=
4
9
×
2
2
=
8
18
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