Question

the price of a diamond ifs directly proportional to the square of its weight. the diamond broke in four parts in such a way that weights of those part were in the ratio of 1:2:3:4. if the total price of the diamond decreased by Rs. 70,000, then what was the price of original diamond?

**\\\((please don't use any x,y or z))///**​

Answer 1

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Cost of diamond =k(weight) \2

8000=k(10) /2

k= 100/8000 =80

Diamond was broke into two pieces = 3x+2x=10,

5x=10⇒x=2

Ist part: 3x=6

IInd part: 2x=4

Ist part; cost⇒80×36=2880

IInd part; cost⇒80×16=1280

Total cost = 2880+1280=4160

So loss = 8000−4160=3840....☺

Answer 2

Answer:

sorry cannot answer without x,y,z

Step-by-step explanation:

but pls mark me as brainliest