Math, asked by fatima2612, 1 year ago

the price of a horse and carriage is rupees 625 and the price of the horse is rupees 75 more than that of the carriage. find the price of each .

Answers

Answered by suryanshagrawal
28

Let the price of carriage be Rs. x

Then price of horse = Rs. (75 + x)

Price of Horse + price of carriage = Rs.625

=> x + 75 + x = 625

=> 2x + 75 = 625

=> 2x = 625 - 75

=> 2x = 550

=> x = 550/2

=> x = 275


Price of carriage = x = Rs. 275

Price of horse = (75+x) = 75+275 = Rs.350



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Answered by vibhakumari1231
0

Answer:

horse Rs is350, carriage Rs 2750

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