Math, asked by priyanavelkar, 2 months ago

the price of a house aappreciated in the ratio 5:7 in 2 years. if its cost was rs. 2250000 before 2 years. find its cost now​

Answers

Answered by BrainlyTwinklingstar
2

Given :

Cost of the house 2 years ago : ₹2250000

Ratio of appreciation of home : 5:7

To find :

The present cost of the home.

Solution :

Let the cost of the house before one year be m.

Cost of the home one year ago :

\sf \dashrightarrow m - 5:7 \: of \: m = 2250000

\sf \dashrightarrow m - \dfrac{5}{7} \: of \: m = 2250000

\sf \dashrightarrow m - \dfrac{5}{7} \times m = 2250000

\sf \dashrightarrow m - \dfrac{5m}{7} = 2250000

\sf \dashrightarrow \dfrac{7m - 5m}{7} = 2250000

\sf \dashrightarrow \dfrac{2m}{7} = 2250000

\sf \dashrightarrow 2m = 2250000 \times 7

\sf \dashrightarrow 2m = 15750000

\sf \dashrightarrow m = \dfrac{15750000}{2}

\sf \dashrightarrow m = 7875000

Now, let's find the present cost of the house.

Present cost of the house :

Let the present cost of the house be n.

\sf \dashrightarrow n - 5:7 \: of \: n = 7875000

\sf \dashrightarrow n - \dfrac{5}{7} \: of \: n = 7875000

\sf \dashrightarrow n - \dfrac{5n}{7} = 7875000

\sf \dashrightarrow \dfrac{7n - 5n}{7} = 7875000

\sf \dashrightarrow \dfrac{2n}{7} = 7875000

\sf \dashrightarrow 2n = 787500 \times 7

\sf \dashrightarrow 2n = 5512500

\sf \dashrightarrow n = \dfrac{5512500}{2}

\sf \dashrightarrow n = 2757250

Hence, the present cost of the house is ₹2757250.

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