Question

The price of a mobile increased by 8%, if's increase price is ₹24975. What is the original price?

⭐Only Quality Answer ⭐​

Answer 1

Answer:

Solutions:

let the original price be = ₹ x

increased price = ₹24975

increase percent = 8%

so,

x×8/100 = 24975 - x

x× 2/25 = 24975-x

2x= 25(24975-x)

2x = 624375 - 25x

27x = 624375

x= ₹(624375÷27)

x= ₹ 23125

so, the original price is ₹ 23125

Answer 2

Answer:

The original price is ₹23125.

Step-by-step explanation:

Given,

Increased price = ₹24975

Rate of increase = 8%

To Find:-

What is original price?

1st Method:-

Assume the original prize is 'x'.

$8\% \: of \: x = \frac{8 + x}{100} \\ \\ therefore \: 8\% \: of \: x = \frac{2x}{25} \\ \\ increased \: price = x+ \frac{2x}{25} \\ \\ = \frac{27x}{25} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Also given that increased prize is ₹24975.

Therefore, according to question,

$24975 = \frac{27x}{25} \\ \\ x = \frac{24975 \times 25}{27} \\ \\ x = 23125$

Therefore, original price = ₹23125.

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2nd Method:-

Assume the original price is ₹ 'x'

Formula:-

$increased \: price = original \: price \\ = (1 + \frac{increased \: price \: (r)}{100} )$

On interesting the values in the furmula,

We gets,

$\implies\large24975 = x(1+\frac{8}{100})$

$\implies\large24975 = x(\frac{100+8}{100})$

$\implies\large24975 = \frac{x\times{108}}{100}$

$\large\implies{x=\frac{24975\times{100}}{108}}$

$\implies\large{x=23125}$

Therefore, Original price

= ₹23125

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More to Know:

• Transposing a number (I.e., changing the side of the number) is the same as adding or subtracting the number from both sides.

• Changing side is called transposing. While transposing a number, change its sign.

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$\footnotesize Answered\:by\:@TheBrainlyBot$