Question

the price of a notebook was increased by x percent to bring the price to earlier level it had to be reduced by 16 whole 2 by 3% find the value of x​

Answer 1

$\huge\bold\green{\underline{Solution:}}$

$\bold\green{\underline{Let:}}$

The price of notebook be 100

$\bold\green{\underline{Given:}}$

X% increased in the price of notebook

so,

The price of notebook=100+X/100*100

The price of notebook=100+X

Than,the price of notebook is reduced by 16whole2/3%

Thus

The price of notebook=(100+X)*50/100*3

The price of notebook=(100+X)*50/300

Now,

According to the above information

$100 + x - ( \frac{100 + x) \times 50}{300} ) = 100$

• Here, we take common (100+x)

$100 + x(1 - \frac{50}{300} ) = 100 \\ \\ 100 + x( \frac{300 - 50}{300} ) = 100 \\ \\ (100 + x) \times \frac{250}{300} = 100 \\ \\ 100 + x = \frac{100 \times 300}{250} \\ \\ 100 + x = 120 \\ \\ x = 120 - 100 \\ \\ x = 20\%$

Hence,

The price to earlier level to increase 20%

$\bold\orange{\underline{The\: value\:of\:X=20\%}}$

Answer 2

Answer:

\bold\green{\underline{Let:}}

Let:

The price of notebook be 100

\bold\green{\underline{Given:}}

Given:

X% increased in the price of notebook

so,

The price of notebook=100+X/100*100

The price of notebook=100+X

Than,the price of notebook is reduced by 16whole2/3%

Thus

The price of notebook=(100+X)*50/100*3

The price of notebook=(100+X)*50/300

Now,

According to the above information

100 + x - ( \frac{100 + x) \times 50}{300} ) = 100100+x−(

300

100+x)×50

)=100

Here, we take common (100+x)

$$\begin{lgathered}100 + x(1 - \frac{50}{300} ) = 100 \\ \\ 100 + x( \frac{300 - 50}{300} ) = 100 \\ \\ (100 + x) \times \frac{250}{300} = 100 \\ \\ 100 + x = \frac{100 \times 300}{250} \\ \\ 100 + x = 120 \\ \\ x = 120 - 100 \\ \\ x = 20\%\end{lgathered}$$

Hence,

The price to earlier level to increase 20%

$$\bold\orange{\underline{The\: value\:of\:X=20\%}}$$