The price of a product first went up 10% and then down 10% . When was the price lower, initially or finally
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Let the original price be x.
⇒Price after 1st being increased by 10%(initially)=x+10% of x
=x+x/10=11x/10.
⇒Price after 2ndly being decreased by 10% (finally)=11x/10-10% of 11x/10
=11x/10-11x/100
=(110x-11x)/100=99x/100.
Clearly , 11x/10>x>99x/100.
So , the price was lower finally at 99x/100
by (finding the percentage)=x/100/x*100 %=1%
.Ans:>The price was lower finally at 99x/100 by 1%.
=======================================
Click on the yellow button below please.
Its my 50th answer from Maths (In brainly.in).
⇒Price after 1st being increased by 10%(initially)=x+10% of x
=x+x/10=11x/10.
⇒Price after 2ndly being decreased by 10% (finally)=11x/10-10% of 11x/10
=11x/10-11x/100
=(110x-11x)/100=99x/100.
Clearly , 11x/10>x>99x/100.
So , the price was lower finally at 99x/100
by (finding the percentage)=x/100/x*100 %=1%
.Ans:>The price was lower finally at 99x/100 by 1%.
=======================================
Click on the yellow button below please.
Its my 50th answer from Maths (In brainly.in).
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