Math, asked by Tajvadakkan, 1 month ago

The price of a product was increased by 15 % and they 20 % .how many % was the price increased together.​

Answers

Answered by tennetiraj86
1

Step-by-step explanation:

Given :-

The price of a product was increased by 15 % and then 20 % .

To find :-

How much % was the price increased together?

Solution :-

Let the Price of the product be Rs. X

The increasing percentage in the product = 15%

Increasing price in the product

=> 15% of the price of the product

=> 15% of X

=> (15/100)×X

=> (3/20)×X

=> 3X/20

The new price of the product

=> X + (3X/20)

=> (20X+3X)/20

=> 23X/20

The new price after increasing 15% = Rs. 23X/20

Then,

Again it is increased by 20%

So,

The new price of the product

=> Previous price + increasing price

=> (23X/20) + 20% of (23X/20)

=> (23X/20)+(20/100)×(23X/20)

=> (23X/20)+(1/5)×(23X/20)

=> (23X/20)+(23X/100)

=> (115X+23X)/100

=> 138X/100

=> 69X/50

The final Price = Rs. 69X/50

Increasing in the product

=> New price - Original price

=> (69X/50) - X

=> (69X-50X)/50

=> 19X/50

Now,

Increased percentage in the product

=> (Increasing price /Original Price )×100

=> [(19X/50)/X]×100

=> (19X/50X)×100

=> (19/50)×100

=> (19×100)/50

=> 19×2

=> 38%

Therefore, the percentage = 38%

Answer:-

The required percentage is increased in the price of the product after increasing is 38%

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