Math, asked by kendalwoods0456, 10 months ago

The price of a ring was increased by 9% to £1800. What was the price before the increase?

Answers

Answered by MavisRee
25

Answer:

The price of the ring before the increase was £ 1651.37

Step-by-step explanation:

Let the price of a ring before the increase be x

New price = £ 1800

Percentage increase = 9\%

Thus, we ge

 x + (\,9\% \times x )\, = 1800\\\\ x + (\,\frac{9}{100} \times x)\, = 1800 \\\\x + \frac{9x}{100} = 1800\\\\ \frac{109x}{100} = 1800 \\\\ x = 1800 \times \frac{100}{109}\\\\x = \frac{180000}{109}\\\\ x = 1651.37

Thus, the price of the ring before the increase was £ 1651.37

Answered by lakshaysoni01279473
13

Answer:

The price of a ring was increased by 9% to £1800. What was the price before the increase?

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