Question

The price of a scooter depreciates by 2% of its value at the beginning of each year. Find the sale value of the scooter after 3 years,if its present sale value is 12000 rupees​

Answer 1

let the value was 100

since it depreciates by 2% each year.

so after 3 years it's value will be

$= 100 {( \frac{100 - 2}{100} )}^{3} \\ = 100 {( \frac{98}{100}) }^{3} \\ = \frac{100 \times 941192}{1000000} \\ = \frac{1 \times 941192}{10000} \\ = 94.12$

if it's present value is 100, then it's old value was 94.12

if it's present value is 1, then it's old value was 100/94.12.

if it's present value is 12000, then it's old value is

$= \frac{100}{94.12} \times 1200 \\ = \frac{100 \times 1200}{94.12} \\ = 1274.96 \\ = 1275$