Question

The price of a smartphone is 5000 more
than the cost of two feature phones. If
the cost of 4 feature phones and two
smartphone is 88,000, then find the cost
of a smartphone and a feature phone.​

Answer 1

$\underline{\bf Given}:$ ↴

Here in this question, it is given that the price of a smartphone is 5000 more than the cost of two feature phones and it is also mentioned that the cost of 4 feature phones and two smartphones is 88,000.

$\bf \underline{To \: find} :$ ↴

We have to find the cost of a smartphone and a feature phone

$\bf \:\underline{\underline{Solution}} :$ ↴

$\sf \: \underline {Let \: us \: assume \: that},$

$\sf \implies The \: cost \: of \: a \: smartphone \: be \: (A)$

$\sf \implies The \: cost \: of \: a \: feature \: phone \: be \: (B)$

$\sf \: \underline{According \: to \: question},$

$\bf \: Case \: (1) :$ ↴

$\small \sf \: The \: price \: of \: a \: smartphone \: is \: Rs. \: 5000 \: more \: than \: the \: cost \: \: of \: two \: feature \: phones .$

$\red{ \sf \implies A =2B +5000 \: \: \: \: \bf{[Equation : 1] }}$

$\bf \: Case \: (2) :$ ↴

$\small \sf \: The \: cost \: of \: 4 \: feature \: phones \: and \: two \: smartphones \: is \: Rs. \: 88000 .$

$\red{ \sf \implies 4B +2A=88000 \: \: \: \: \bf{[Equation : 2] }}$

$\bf \: Now,$

$\sf \: Finding \: the \: cost \: of \: a \: smartphone \: and \: a \: feature \: phone.$

$\sf \: In \: equation - 2,$

$\bf \implies 4B +2A=88000$

$\sf \implies 4B +(2B + 5000)=88000$

$\sf \implies 4B +4B + 1000=88000$

$\sf \implies 8B + 1000=88000$

$\sf \implies 8B =88000 - 1000$

$\sf \implies 8B =78000$

$\sf \implies B = \dfrac{78000}{8}$

$\sf \implies B = \: \dfrac{\!\!\!\not7\!\!\!\not8\!\!\!\not0\!\!\!\not0\!\!\!\not0}{\!\!\!\not8}$

$\sf \implies B = 9750$

$\underline{ \red{ \sf The \: cost \: of \: four \: feature \: phone = Rs. \: 9750}}$

$\sf Now \: we \: will \: find \: the \: cost \: of \: a \: smartphone.$

$\sf \: For \: that, we \: have \: to \: put \: the \: value \: of \: B \: (9750) \: into \: [Equation - 1]$

$\sf \: In \: equation - 1,$

$\bf \implies A =2B +5000$

$\sf \implies A =2 \times 9750 +5000$

$\sf \implies A =19500 +5000$

$\sf \implies A =24500$

$\underline{ \red{ \sf The \: cost \: of \: Smartphone = Rs. \: 24500}}$

Answer 2

Given:

• The price of 1 smartphone is 5000 more than the cost of 2 feature phones.
• cost of 4 feature phones and two smartphone is 88,000.

To find :

• Cost of 1 smartphone and 1 feature phone ?

Solution:

Given that cost of 2 feature phone is equals cost of 1 smartphone phone.

Let suppose that,

• Cost of 2 feature phone is x ••••(i)

Therefore,

• Cost of 1 smartphone will be x + 5000 ••••(ii)

Now, If cost of 2 feature phone is x and cost of 1 smartphone is x + 5000,

Then,

• Cost of 4 feature phone = 2x ••••(iii)
• Cost of 2 smartphone = 2(x + 5000) = 2x + 10000 •••(iv)

According to question,

88000 = Cost of 4 feature phone + 2 smartphone

→ 88000 = 2x + (2x + 5000)

→ 88000 = 4x + 10000

→ 4x = 88000 - 10000

→ 4x = 78000

→ x = 78000/4

→ x = 19500

Therefore,

• Cost of 2 feature phone is x = 19500

Now,

We are asked to find cost of 1 feature phone and 1 smartphone.

Therefore,

• Cost of 1 feature phone = $\dfrac{x}{2}$ = $\dfrac{19500}{2}$= 9750
• Cost of 1 smartphone phone = x + 5000 = 9750 + 5000 = 24500

Hence,

$\small\boxed{\tt{\green{Cost\:of\:1\: feature\:phone\:is\:₹97500\: and\:of\:1\: smartphone\:is\:₹24500}}}$