Math, asked by ruhi9157, 1 month ago

The price of a smartphone is 5000 more
than the cost of two feature phones. If
the cost of 4 feature phones and two
smartphone is 88,000, then find the cost
of a smartphone and a feature phone.​

Answers

Answered by ᏟrєєpyᎷєss
2

Answer:

Cost of a smartphone = Rs. 24500

Cost of a feature phone = Rs. 9750

Step-by-step explanation:

To Find:

The cost of a smartphone and a feature phone.

Let us assume:

The cost of a smartphone be x.

The cost of a feature phone be y.

The price of a smartphone is 5000 more than the cost of two feature phones.

i.e., x = 2y + 5000 _____(i)

The cost of 4 feature phones and two smartphone is 88000.

i.e., 4y + 2x = 88000 _____(ii)

Finding the cost of a smartphone and a feature phone:

In equation (ii).

⟿ 4y + 2x = 88000

Substituting the value of x from eqⁿ(i).

⟿ 4y + 2(2y + 5000) = 88000

⟿ 4y + 4y + 10000 = 88000

⟿ 8y = 88000 - 10000

⟿ 8y = 78000

⟿ y = 78000/8

⟿ y = 9750

∴ Cost of a feature phone = Rs. 9750

In equation (i).

⟿ x = 2y + 5000

⟿ x = 2(9750) + 5000

⟿ x = 19500 + 5000

⟿ x = 24500

∴ Cost of a smartphone = Rs. 24500

Answered by Anonymous
2

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Cost of a smartphone = Rs. 24500

Cost of a feature phone = Rs. 9750

Step-by-step explanation:

To Find:

The cost of a smartphone and a feature phone.

Let us assume:

The cost of a smartphone be x.

The cost of a feature phone be y.

The price of a smartphone is 5000 more than the cost of two feature phones.

i.e., x = 2y + 5000

The cost of 4 feature phones and two smartphone is 88000.

i.e., 4y + 2x = 88000

(ii)Finding the cost of a smartphone and a feature phone:

In equation (ii).

4y + 2x=88000

Substituting the value of x from eq"(i).

4y+2(2y + 5000) = 88000

4y + 4y +10000 = 88000

8y=88000-10000

8y = 78000

y = 78000/8

y = 9750

.. Cost of a feature phone = Rs. 9750

In equation (i).

x = 2y + 5000

x = 2(9750) + 5000

x = 19500 + 5000

x = 24500

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