The price of a train ticket has direct relation with the length of journey. If RS 504 is charged for 4x km long journey. Find the charge for a 4/2 km long journey.
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Step-by-step explanation:
If the relationship is direct then price α length price
= k × length 504 = k ×4x So k =5044x
Now charge or price for y2 km = k×y2=5044x×y2=Rs. 252y4xRegardsDear
If the relationship is direct then price α length price = k × length 504 = k ×4x
So k =5044xNow charge or price for y2 km = k×y2=5044x×y2=Rs. 252y4x
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