Question

the price of an article increased by 20% after some days the price reduced by 20% is the reduced price of an article is more or less than the original price by how many percent​

Answer 1

Answer:

Let the price be x

Price after an increase of 20% = x + 20x/100 = 120x/100 = 6x/5

Now, if the price is 6x/5

=> price after 20% decrease = 6x/5 [(100-20)/100]

= 6x/5 (80/100)

= 480x/500

= 96x/100

= 96% of x

Therefore, final price of article will 4% less than the original price.

Answer 2

Answer:

SOLUTION:

CASE I

Let initial cost price be x Rs.

Profit = 20/100 * x = x/5

So selling price = x + x/5 = 6x/5

CASE II

Cost price = x + 50

Selling Price = 6x/5 + 30

Profit = (6x/5 + 30) - (x + 50) = x/5 -20

Profit Percentage = (x/5 - 20) / (x + 50) * 100

But in according to the question profit percentage = 20 - 10/3 = 50/3 %

So (x/5 - 20) / (x + 50) * 100 = 50/3

∴ (x/5 - 20) / (x + 50) = 1/6

∴ 6x/5 - 120 = x + 50

∴ x/5 = 170

∴ x = 850

So original cost price = Rs 850