Math, asked by mowror, 11 months ago

the price of camcorder originally marked at $2000 was reduced by 20% during a special promotion. the price was then reduced by an additional 30% to clear the stock. what was the sale price for each reduction. will the final price be the same if the camcorder was reduced by 30% first and followed by 20%?

Answers

Answered by NirmalPandya
1

Given:

  • Original price of camcorder is $2000.
  • It was reduced by 20 % first
  • Then it was reduced by 30%

To find:

  • Selling price after each reduction
  • Whether price would remain same if reduction was 30% first and 20% later.

Solution:

  • Camcorder price was reduced by 20 %.
  • So selling price after 1st reduction becomes 2000 - (2000 * 20/100).
  • So selling price after 1st reduction = 2000-400 = 1600.
  • Selling price after first reduction was $1600.
  • Selling price after second reduction (30%) is 1600 - (1600*30/100)
  • Selling price after second reduction = 1600-480 = 1120.
  • Selling price after second reduction was $1120

  • Now, if first reduction was 30%, price would become $1400.
  • After that if 20% reduction was applied, final price would become $1120.
  • Hence, we see that final price remains same even if order of the 20% and 30% reduction is changed.

Answer:

  • After 1st reduction cost was $1600 and after second reduction cost was $1120.
  • If 30% reduction is applied first and 20 % reduction is applied later, sale price remains same as $1120.

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