Math, asked by amanshaikh5439, 3 months ago

*The price of one box is (a - 7) Rs. What is the total cost of (a + 7) boxes?*

1️⃣ ₹(a² - 14a + 49)
2️⃣ ₹(a² - 49)
3️⃣ ₹(a² + 14a + 49)
4️⃣ ₹(a² + 49)​

Answers

Answered by Anonymous
1

Answer:

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Step-by-step explanation:

Given : Cost of one box = Rs. (a-7)

To find : Cost of (a+7) boxes

Solution :

Cost_{(1 \: box)} = (a - 7) \\  \\ Total \:  \: cost = cost_{(1 \: box)} \times (a  +  7) \\  \\ Total \:  \: cost = (a - 7)\times (a  +  7) \\  \\ Cost_{(a + 7) \: boxes} = (a - 7)(a  +  7) \\  \\ Using \:  \: identity \: (x - y)(x + y) = x {}^{2}  -  {y}^{2}  \\  \\ Total \: cost  = (a) {}^{2}  - (7) {}^{2}  \\  \\ \bold\red{Total \: Cost  =a {}^{2}  - 49}

∴ Total cost of (a+7) boxes is Rs. a²-49

Answered by jaydebpodder
1

Answer:

then the cost of (a+7) is a^2 - 49

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