Math, asked by anjujaiswal302, 11 months ago

The price of silver at present is Rs 8,000 per kg . Its price increases at the rate of 5% in the first year, decrease at the rate of 10% in the second year and again decrease further at the rate of 4% in the third year. Find its price per kg at the end of the third year.

Answers

Answered by hardikgarg746
26

Answer:

Step-by-step explanation:

Present price - 8000

First year - increase of 5% i.e. 5/100*8000=400

Therefore, 8000+400=8400

Second year= decrease of 10%

10/100*8400=840

8400-840= 7560

Third year = decrease 4%

4/100*7560= 302.4

7560-302.4= 7257.6

That was an easy one

Answered by pratiksha1119
3

Step-by-step explanation:

Given:-

Cost of Silver= 800

Increase of 5% in first year.

Decrease of 10% in second year.

Increase of 4% in third year.

To find:-

The cost of Silver in the third year.

Solution:-

First year,

8000 x 5/100= 400

Increased,

8000+400= 8400

Second year,

8400 x 10/100= 840

Decreased,

8400-840= 7560

Third year,

7560 x 4/100= 302.4

Increased,

7560+302.4= 7862.4

Thus, the price in the third year is Rs. 7862.4.

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