Question

the price of sweater increased by 8% if it's increase price is 1566 . what is the original price​

Answer 1

PLEASE REFER TO THE ATTACHMENT.

I HOPE IT HELPS. ☺FOLLOW ME ✌

Answer 2

Given ,

Increased Price = ₹ 1566

Rate of Increase = 8%

To Find :-

The original price.

Ist Method :-

Let the original price be ₹x

8% of x = $\dfrac{8 \times x}{100}$

therefore 8% of x = $\dfrac{2x}{25}$

Increased Price = x + $\dfrac{2x}{25}$

= $\dfrac{25x + 2x}{25}$

= $\dfrac{27x}{25}$

Also given that, Increased Price is ₹1566

Therefore, acc to question,

₹1566 = $\dfrac{27x}{25}$

=> x = $\dfrac{1566 \times 25}{27}$

=> x = ₹1450

Therefore, Original Price = ₹1450

2nd Method :-

Let the original price be ₹x

Formula :-

Increased Price = Original Price $(1 + {\dfrac{r}{100}})$

On Inserting the values in the formula

We get ,

$1566 = x(1 + {\dfrac{8}{100}})$

$1566 = x({\dfrac{100 + 8}{100}})$

$1566 = {\dfrac{x \times 108}{100}}$

$x = {\dfrac{1566 \times 100}{108}}$

x = 1450

Therefore, Original Price = ₹1450

Short-hands Used :-

IP = Increased Price.

OP = Original Price.

R = Rate.

Acc = According.

$\bf{ \underline{Some Formulae}} \\ \\ \rightarrow \quad \sf P = \dfrac{100 \times S.I}{R \times T} \\ \\ \\ \rightarrow \quad T = \dfrac{100 \times S.I}{P \times R} \\ \\ \\ \rightarrow \quad R = \dfrac{100 \times S.I}{P \times T} \\ \\ \\ \rightarrow \quad A = P + S.I \\ \\ \\ \rightarrow \quad S.I = \dfrac{P \times R \times T}{100}$