The price of the machine by 10% every year. If the machine is bought for rupees I 18000 and sold after 3 years what price will it fetch
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Value- 18000
Time-3 years
Rate- 10% p.a
A=P[1-r/100]
= 18000[1-10/100]
=18000×11/10×11/10
=180×11×11
= 21780
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10% of 40500 = 4050
value of machine after one year = 40500-4050 = 36450
again 10% of 36450 = 3645
therefore the value of machine after two years = 36450-3645=32805.
now let the value of machine b4 one year would
be x then
x-x*10/100=40500,
9x/10=40500
x= 45000
again, let the value of machine b4 two years would y
then,
y-y*10/100=45000
9y/10 = 45000
y = 50000
therefore the value of machine after two years and b4 two years are respectively,
32805 & 50000
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