Question

the price of three chairs and two tables in 4500 rupees and price of 5 chairs and 3 tables is 7000 Rupees then find the total price of two chairs and ✌️
tables ​

Answer 1

Let chairs be c,tables be t

3c+2t=4500------(1)

5c+3t=7000------(2)

multiple equation (1) with 3 & (2) with 2

9c+6t=13500

10c+6t=14000

------------------------

c=5000

substitute c value in equation (1)

1500+2t=4500

2t=4500-1500

2t=3000

t=1500

2c+2t=2×5000+2×1500

=10000+3000=13000

Answer 2

Answer:

The total price of 2 chairs and 2 tables is rupees 4000.

Step-by-step explanation:

Let the price of chair be rupees x and that of table be rupees y. Then from the first condition,

3x + 2y = 4500 ... (1)

From the second condition,

5x + 3y = 7000 ... (2)

Multiplying equation (1) by 3 and equation (2) by 2,

9x + 6y = 13500 ... (3)

10x + 6y = 14000 ... (4)

Subtracting equation (3) from equation (4),

(10x + 6y = 14000)

-(9x + 6y = 13500)

——————————

x + 0 = 500

=> 2x = 2 × 500 = 1000 ... (5)

Substituting x = 599 in equation (1)

3(500) + 2y = 4500

=> 1500 + 2y = 4500

=> 2y = 4500 - 1500

=> 2y = 3000 ... (6)

Now, the price of 2 chairs and 2 tables is

Rupees(1000 + 3000) [From (5) and (6)]

= rupees 4000

Hence, the total price of 2 chairs and 2 tables is rupees 4000.

Hope it helps :)