Math, asked by saipawan9, 11 months ago

the price of two bags arethe in ratio 8:7if the expensive bag is 5000 more than the cheaper one then calculate the total price one has to pay if he wishes to buy the bags​

Answers

Answered by nilanjandascr7
10

Answer:

75000

Step-by-step explanation:

the prices are 8x,7x

7x+5000=8x

x=5000

therefore, the total cost=(7*5000)+(8*5000)=35000+40000=75000

Answered by lovingheart
0

Answer:

The income of X and Y is Rs. 6000 and Rs. 5250

Step-by-step explanation:

Step 1:

Let the income of X be Rs. 'p' and his expenditure be Rs. 'q'.

And, income of Y be Rs. 'r' and his expenditure be rs. 's'.

Therefore,

Step 2:

p / r = 8 / 7  

⇒ p = 8r / 7

Similarly,

Q / s = 19/16

⇒ q = 19s/16

Step 3:

Savings of X = p - q

⇒ 1250 = 8r/7 – 19s/16

Taking L.C.M. of the denominators and then solving it, we get.

⇒ 1250 = (128r – 133s)/112

⇒ 128r – 133s = (1250*112)

⇒ 128r – 133s = 140000 .............(1)

Step 4:

Savings of Y = r - s

⇒ r = 1250 + s ............(2)

Substituting (2) in (1), we get.

⇒ 128 x (1250 + s) – 133s = 140000

⇒ 160000 + 128s – 133s = 140000

⇒ 128s – 133s = 140000 - 160000

⇒ - 5s = - 20000

⇒ 5s = 20000

⇒ s = 20000/5

⇒ s = 4000

Step 5:

Putting s = 4000 in (2), we get.

Now, c = 1250 + 4000

⇒ c = 5250

Now, putting r =  5250 in a = 8r/7

⇒ p = (8*5250)/7

⇒ p = 42000/7

⇒ p = 6000

And,q = 6000 - 1250  

q = 4750

Step 6:

Hence, the income of X and Y is Rs. 6000 and Rs. 5250

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