the price of two bags arethe in ratio 8:7if the expensive bag is 5000 more than the cheaper one then calculate the total price one has to pay if he wishes to buy the bags
Answers
Answer:
75000
Step-by-step explanation:
the prices are 8x,7x
7x+5000=8x
x=5000
therefore, the total cost=(7*5000)+(8*5000)=35000+40000=75000
Answer:
The income of X and Y is Rs. 6000 and Rs. 5250
Step-by-step explanation:
Step 1:
Let the income of X be Rs. 'p' and his expenditure be Rs. 'q'.
And, income of Y be Rs. 'r' and his expenditure be rs. 's'.
Therefore,
Step 2:
p / r = 8 / 7
⇒ p = 8r / 7
Similarly,
Q / s = 19/16
⇒ q = 19s/16
Step 3:
Savings of X = p - q
⇒ 1250 = 8r/7 – 19s/16
Taking L.C.M. of the denominators and then solving it, we get.
⇒ 1250 = (128r – 133s)/112
⇒ 128r – 133s = (1250*112)
⇒ 128r – 133s = 140000 .............(1)
Step 4:
Savings of Y = r - s
⇒ r = 1250 + s ............(2)
Substituting (2) in (1), we get.
⇒ 128 x (1250 + s) – 133s = 140000
⇒ 160000 + 128s – 133s = 140000
⇒ 128s – 133s = 140000 - 160000
⇒ - 5s = - 20000
⇒ 5s = 20000
⇒ s = 20000/5
⇒ s = 4000
Step 5:
Putting s = 4000 in (2), we get.
Now, c = 1250 + 4000
⇒ c = 5250
Now, putting r = 5250 in a = 8r/7
⇒ p = (8*5250)/7
⇒ p = 42000/7
⇒ p = 6000
And,q = 6000 - 1250
q = 4750
Step 6:
Hence, the income of X and Y is Rs. 6000 and Rs. 5250