Question

the price of two cups and three saucer is 680 if the cup cost rupees 20 more than a saucer find the cost of each​

Answer 1

Step-by-step explanation:

let price of cup be x and saucer be y

then, 2x+3y =680

given :

x=(20+y)

therefore, 2(20+y)+3y=680

40+2y+3y=680

40+5y=680

5y=680-40=640

y=640÷5=128

saucer=y=128

cup= x= 128+20=148

2(148)+3(128)=680