Math, asked by sunaifirfan, 9 months ago

The price of two product A and B are in the ratio
7: 5. If product A cost Rs. 8000 more than product
B, find the cost of product B.

Answers

Answered by nihel34
0

Answer:

B=20000

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Step-by-step explanation:

Let a and b be 7x and 5x

7x-5x=8000

2x=8000

x=4000

B=5x=20000

Answered by ajajit9217
0

Answer:

Cost of product B is Rs.20,000

Step-by-step explanation:

Let price of product B= Rs. x

∴ Price of Product A = Rs. 8000 +x

Ratio of price of product A and B = 7 : 5= 7/5

Ratio of the price of A and B = Price of A /Price of B

                                7 /5  = (8000 +x)/x

By doing cross multiplication,

               7x = 5× (8000 + x)

               7x = 5×8000 +5x

     7x -5x = 40000

         2x= 40000

           x = 40000 /2

               = 20000

Answered by steffiaspinno
0

The price of product B is Rs 20000.

Step-by-step explanation:

  • Let the price of product A be '7x', and that of product B be '5x'.
  • It is given that cost of product A is 8000 more than the cost of product B.
  • So, if their prices are subtracted, the result should be 8000.

Thus,

7x - 5x = 8000

2x = 8000

x = 4000

  • Hence, the price of product B = 5x =  5\times 4000 =  Rs 20000
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