Question

. The price of wheat goes up by 10%. By how
much percent should Riya reduce her wheat
consumption, so that her expenditure on what
does not increase.​

Answer 1

we use formula $\frac{R.100}{100+R}$

from question we have R = 10%

so the percentage decrease

= $\frac{(10).100}{100+10}$

=$\frac{1000}{110}$

=$\frac{100}{11}$

= 9.09 % ans

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Answer 2

Answer:

we use formula \frac{R.100}{100+R}

we use formula \frac{R.100}{100+R} 100+R

we use formula \frac{R.100}{100+R} 100+RR.100

we use formula \frac{R.100}{100+R} 100+RR.100

we use formula \frac{R.100}{100+R} 100+RR.100

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease= \frac{(10).100}{100+10}

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease= \frac{(10).100}{100+10} 100+10

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease= \frac{(10).100}{100+10} 100+10(10).100

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease= \frac{(10).100}{100+10} 100+10(10).100

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease= \frac{(10).100}{100+10} 100+10(10).100

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease= \frac{(10).100}{100+10} 100+10(10).100 =\frac{1000}{110}

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease= \frac{(10).100}{100+10} 100+10(10).100 =\frac{1000}{110} 110

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease= \frac{(10).100}{100+10} 100+10(10).100 =\frac{1000}{110} 1101000

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease= \frac{(10).100}{100+10} 100+10(10).100 =\frac{1000}{110} 1101000

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease= \frac{(10).100}{100+10} 100+10(10).100 =\frac{1000}{110} 1101000

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease= \frac{(10).100}{100+10} 100+10(10).100 =\frac{1000}{110} 1101000 =\frac{100}{11}

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease= \frac{(10).100}{100+10} 100+10(10).100 =\frac{1000}{110} 1101000 =\frac{100}{11} 11

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease= \frac{(10).100}{100+10} 100+10(10).100 =\frac{1000}{110} 1101000 =\frac{100}{11} 11100

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease= \frac{(10).100}{100+10} 100+10(10).100 =\frac{1000}{110} 1101000 =\frac{100}{11} 11100

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease= \frac{(10).100}{100+10} 100+10(10).100 =\frac{1000}{110} 1101000 =\frac{100}{11} 11100

we use formula \frac{R.100}{100+R} 100+RR.100 from question we have R = 10%so the percentage decrease= \frac{(10).100}{100+10} 100+10(10).100 =\frac{1000}{110} 1101000 =\frac{100}{11} 11100 = 9.09 % ans

Step-by-step explanation:

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