The price P per unit at which a company can sell all that it produces is given by the function P(x) = 300 — 4x. The cost function is c(x) = 500 + 28x where x is the number of units produced. Find x so that the profit is maximum.
profswh:
is the answer 37
Answers
Answered by
11
total selling price = P.x
= (300 - 4x)x
profit = P*x - C
= (300 - 4x)x - (500 +28x)
for this to be maximum, (300 - 4x)x should be maximum
maximum value of a quadratic equation = -b/2a
= -300/(-2*4)
= 37.5
this can yield two values 37 and 38. you will find that P.x is same for both value
so now C is less for 37
so the answer is 37
= (300 - 4x)x
profit = P*x - C
= (300 - 4x)x - (500 +28x)
for this to be maximum, (300 - 4x)x should be maximum
maximum value of a quadratic equation = -b/2a
= -300/(-2*4)
= 37.5
this can yield two values 37 and 38. you will find that P.x is same for both value
so now C is less for 37
so the answer is 37
Answered by
1
Concept:
Profit means the difference between the selling price and the cost price of a firm.
Given:
We are given that:
The selling price function is:
P(x) = x( 300 - 4 x).
The cost function is :
c(x) = 500 + 28 x
Find:
We need to find x so that the profit is maximum.
Solution:
The selling price function is:
P(x) = x( 300 - 4 x).
The cost function is :
c(x) = 500 + 28 x
Profit function will be:
selling price function - cost function
=300x - 4 x² - (500 + 28 x)
=300 x - 4 x² - 500 - 28 x
P (x) =-4x² +272 x - 500
We will differentiate it with respect to x:
P' (x)=-8x+272.
Put it equal to 0:
8x=272
x=34.
Therefore, x=34, if the profit has to be maximum.
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