The prices of different articles and demand for them is shown in the following
frequency distribution table Find the median of the prices.
Price (Rupees) less then 20 20-40
No. of articles 140 1 100
40-60
80
60-80
60
80-100
I 20
which one of this median class and how
Answers
Answer:
Price No.ofarticles c.f
0−20 140 140
20−40 100 240
40−60 80 320
60−80 60 380
80−100 20 400
N=400
2
N
= 2
400
=200
∴ Medianclass=20−40
We have, l=20,c.f=140,f=100 and h=20
⇒ Median=l+
f
2
N
−c.f
×h
=20+
100
200−140
×20
=20+12
=32
Step-by-step explanation:
median of the prices = 32
Step-by-step explanation:
Price (Rupees) : No. of articles Cumulatve Frequency
20 less than 140 140
20-40 100 240
40-60 80 320
60-80 60 380
80-100 20 400
Median Lies in 20-40
Estimated Median = 20 + 20 * ((400/2) - 140)/100
= 20 + 20 * 60/100
= 20 + 12
= 32
median of the prices = 32