Question

The primary of a transformer has 400 turns while the secondary has 2000 turns. if the power output from the secondary at 1100 v is 12.1 kw. calculate primary voltage. if the resistance of the primary is 0.2 ohm and that of secondary is 2 ohm and the efficiency is 90%. calculate the heat losses in the primary and secondary coils

Answer 1

Answer:

Explanation:

Turns of the primary transformer = 400

Turns of the secondary transformer = 2000

The relation between voltage drop of a coil and number in terms is given as - N1/N2 =V1/V2

Where N is the number of turns in the coil = 400 and

V is the voltage across the coil = 2000.

Therefore,

1000/V2 = 2000/400

V = 200

Efficiency of transformer = 90%

Thus = Output power/input power = 0.9

= ( 200×I) × 0.9 = 12,000

= 12000/ 180

= 67 approx.

Therefore, the heat loss is 67

Answer 2

Explanation:

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