the prime factor8sation of a natural number n is 2^3×3^2×5^2×7 find the number of consecutive zeroes in n.
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For finding the number of consecutive zeroes the form of 2^m and 5^n should be checked... This one should have only one zero as it has 2^3 but only 5^1
rakshamodi03:
Its 5^2
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