Math, asked by rakshamodi03, 1 year ago

the prime factor8sation of a natural number n is 2^3×3^2×5^2×7 find the number of consecutive zeroes in n.

Answers

Answered by AnnyM
1
For finding the number of consecutive zeroes the form of 2^m and 5^n should be checked... This one should have only one zero as it has 2^3 but only 5^1

rakshamodi03: Its 5^2
rakshamodi03: So i think it will have 2 consecutive zeroes
AnnyM: Yes.. My mistake
Similar questions