the primeter of a rectanglear swimming pool is 154m. Its length is 2m more than twice its breadth . What are the length and the breath of the pool .
Answers
Given:
✰ The primeter of a rectangular swimming pool = 154 m
✰ Length of a rectangular swimming pool is 2 m more than twice its breadth.
To find:
✠ The length of a rectangular swimming pool.
✠ The breadth of a rectangular swimming pool.
Solution:
Let's understand the concept first!
- First we will assume the breadth of a rectangular swimming pool as x.
- Then we know that length of a rectangular swimming pool is 2 m more than twice its breadth, which means we will multipy 2 by its breadth and add 2 which is equal to the length of a rectangular swimming pool.
- We are provided with the perimeter of a rectangle.
- After that using formula of perimeter of rectangle. Putting the values in the formula and then doing the required calculation, we will find the value of x, which is equal to the breadth of the rectangular swimming pool and then by using the value of x we will find the length of a rectangular swimming pool.
Let the breadth of a rectangular swimming pool be x,
Then the length of a rectangular swimming pool = 2x + 2
✭ Perimeter of a rectangle = 2( l + b ) ✭
Here,
- l is the length of the rectangular swimming pool.
- b is the breadth of the rectangular swimming pool.
Putting the values in the formula, we have:
➛ 154 = 2( 2x + 2 + x )
➛ 154 = 2( 3x + 2 )
➛ 154/2 = 3x + 2
➛ 77 = 3x + 2
➛ 77 - 2 = 3x
➛ 75 = 3x
➛ x = 75/3
➛ x = 25 m
∴ The breadth of a rectangular swimming pool = 25 m
Now, find its breadth
➛ The length of a rectangular swimming pool = 2 × 25 + 2
➛ The length of a rectangular swimming pool = 50 + 2
➛ The length of a rectangular swimming pool = 52 m
∴ The length of a rectangular swimming pool = 52 m
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Answer:
Let the length of the pool be denoted by [math]l[/math], and the breadth be denoted by [math]b[/math]
Then, the statement, “Its length is 2 m more than twice its breadth” is equivalent to writing:
[math]l = 2b + 2[/math]
Now, for a rectangle, the perimeter, [math]P,[/math] is given by:
[math]P = 2l + 2b[/math]
Substituting our expression for [math]l[/math] gives:
[math]P = 2(2b+2) + 2b = 6b + 4 = 154[/math]
which we can re-arrange to find:
[math]6b = 150 \implies b = 25[/math]
And plugging this into our expression for [math]l[/math] yields:
[math]l = 2b+2 = 2 \times 25 + 2 = 52[/math]
Thus its length is 52m and its breadth is 25m
Step-by-step explanation: