The primeter of an isosceles triangle is 43/4 cm. If one of its equal sides is 17/6 cm, find the third side.
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Let the equal sides of isosceles traingle be x and unequal side be b.
Then perimeter of isosceles traingle=x+x+b
=2x+b
Now,x=17/6( given) and perimeter=43/4 (given)
putting these values in the equation we get
2 x 17/6+b=43/4
or,17/3+b=43/4
or,b=43/4-17/3
b=61/12 ans
Then perimeter of isosceles traingle=x+x+b
=2x+b
Now,x=17/6( given) and perimeter=43/4 (given)
putting these values in the equation we get
2 x 17/6+b=43/4
or,17/3+b=43/4
or,b=43/4-17/3
b=61/12 ans
Answered by
2
Howdy!!
your answer is ----
Let, ∆ ABC IS A ISOSCELES TRIANGLE
and THIRD SIDE BE C
Given, of of its opposite side is 17/6 cm
so, A= B = 17/6 cm
since , its perimeter is 43/4 cm
therefore , A+B+C = 43/4
= > 17/6+17/6+C = 43/4
= > 34/6 + C = 43/4
= > C = 43/4 - 34/6
= > C = 61/12 cm
hence , its third side is 61/12 cm
hope it help you
your answer is ----
Let, ∆ ABC IS A ISOSCELES TRIANGLE
and THIRD SIDE BE C
Given, of of its opposite side is 17/6 cm
so, A= B = 17/6 cm
since , its perimeter is 43/4 cm
therefore , A+B+C = 43/4
= > 17/6+17/6+C = 43/4
= > 34/6 + C = 43/4
= > C = 43/4 - 34/6
= > C = 61/12 cm
hence , its third side is 61/12 cm
hope it help you
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