The primeter of two squares is 60 and 144 m find perimeter of third sqare equal in area to the sum of first two squares
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8
Hello...
✔️perimeter of 1st square = 60
4a= 60
a= 60÷4
a= 15
✔️area= a²
= (15)²
= 625
✔️perimeter of 2nd square = 144
4A= 144
A= 144/4
= 36
✔️area = A²
= (36)²
= 1296
✔️so,the perimetre of new square formed = 625+1296
=1921
thank you......
✔️perimeter of 1st square = 60
4a= 60
a= 60÷4
a= 15
✔️area= a²
= (15)²
= 625
✔️perimeter of 2nd square = 144
4A= 144
A= 144/4
= 36
✔️area = A²
= (36)²
= 1296
✔️so,the perimetre of new square formed = 625+1296
=1921
thank you......
sony2005:
your have done a small mistake
15 square is 225 not 625
Answered by
1
Given,
the perimeter of the two squares = 60,144m
perimeter of the third square is = sum of thearea of two squares
area of first square is = (60/4)^2
= 225m^2
area of second square is = (144/4)^2
= 36×36=1296m^2
perimeter of the third square is = 225+1296
= 1521m
the perimeter of the two squares = 60,144m
perimeter of the third square is = sum of thearea of two squares
area of first square is = (60/4)^2
= 225m^2
area of second square is = (144/4)^2
= 36×36=1296m^2
perimeter of the third square is = 225+1296
= 1521m
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