Question

The principal if differences in its compound interest and simple interest for a period of 2 years at 4% is rupees 8 is​

Answer 1

Step-by-step explanation:

Compound interest =A−P

C.I.=P(1+100R)n−P=P[[1+10010]4−1]

C.I. =0.4641P

Simple interest, S.I. = 100PNR

S.I.=100P×10×4

S.I. =0.4P

Now .C.I − S.I. =8

⇒0.4641P−0.4P=8

⇒P=0.06418

⇒P= Rs. 124.80

Answer 2

Answer:

Answer

Compound interest =A−P

C.I.=P(1+

100

R

)

n

−P=P[[1+

100

10

]

4

−1]

C.I. =0.4641P

Simple interest, S.I. =

100

PNR

S.I.=

100

P×10×4

S.I. =0.4P

Now .C.I − S.I. =8

⇒0.4641P−0.4P=8

⇒P=

0.0641

8

⇒P= Rs. 124.80

Step-by-step explanation:

I hope help you please yaar follow mark brainlist kerro