Question

The principal sanctioned a certain amount to the librarian to purchase some Mathematics books for the school library. She could buy 80 books casting Rs 90 each from the local book seller. There she approached to the publisher who offered her a 20% discount, Find the number of copies of Mathematics books which she could buy from the publisher for the sanctioned money.

Answer 1

Answer:

$\color{red}{hello}$

Step-by-step explanation:

here is your answer buddy

Answer 2

$Cost \:of \:each \: mathematics \: book = Rs\:90$

$Number \:of \:books \: librarian \: she \\could \: buy = 80$

$Total \:cost = 90 \times 80 \\= Rs \: 7200$

$Cost \:of \:each \:book \: after \: offered \\20\%\: discount = 90 \Big( \frac{100-discount}{100} \Big) \\= 90 \Big( \frac{100-20}{100} \Big) \\= 90 \times \frac{80}{100} \\= 9 \times 8 \\=Rs \:72$

$Now, Number \:of \: Mathematics \:books \\she \: could \:buy \: from \:the \: publisher \\for \:the \: sanctioned \:money \\= \frac{Sanctioned \:money}{cost \:price \: after \: discount }\\= \frac{7200}{72} \\= 100$

Therefore.,

$\red{ Number \:books \:bought \: by }$

$\red { sanctioned \:money } \green {= 100 }$

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