Question

the principal sanctioned a certain amount to the librarian to purchase some mathematics books for the school library. she could buy 80 books casting Rs 90 each from the local book seller. there she approached to the publisher who offered her a 20 %discount. find the number of copies of mathematics books which she could buy from the publisher for the sanctioned money.
Please give me the correct answer it's urgent

Answer 1

Hey,
If she could buy 80 books costing ₹90 that means she had ₹7200 (as 80*90 is 7200)
Publisher
Discount=20%
IE selling price = 80% * 90
= ₹72
So, if the price of 1 book is 72 then
No. of books she can buy= 7200/72
= 100 books
Thus, she can buy 100 maths books from the publisher
Hope it helps

Answer 2

Answer:

Thus, the number of mathematics books which she could buy from the publisher for the sanctioned money is 100.

Step-by-step explanation:

Given,

The school librarian could buy 80 Mathematics books casting Rs.90 each from the local book seller.

Publisher offered her a 20% discount.

We need to find the number of copies of mathematics books which she could buy from the publisher for the sanctioned money?

Sol:  The cost of a Mathematics book = Rs.90

        The cost of 80 Mathematics books = 80*90

                                                                   = Rs.7200

       The Publisher Offered her discount = 20%

       Then, the discount on each mathematics book

                                     $=90*\frac{20}{100} \\=90*\frac{1}{5} \\=Rs.18$

      ∴ After discount, the cost of each book = 90 - 18

                                                                         = Rs.72

     Therefore, the number of mathematics books which she could buy from the publisher for the sanctioned money is

                          n = Total Amount/Cost of each book

                              $=\frac{7200}{72} \\=100$

Thus, the number of mathematics books is 100.