Question

the principal value of cos(π/2-sin^-1 1/2) =?​

Answer 1

Answer:

I think this is the correct answer

Answer 2

$\displaystyle \sf{cos \bigg( \frac{\pi}{2} - {sin}^{ - 1} \frac{1}{2} \bigg) = \frac{1}{2} }$

Given :

The expression

$\displaystyle \sf{cos \bigg( \frac{\pi}{2} - {sin}^{ - 1} \frac{1}{2} \bigg) }$

To find :

The principal value of the expression

Formula :

$\displaystyle \sf{cos \bigg( \frac{\pi}{2} - \theta \bigg) = sin \theta }$

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

$\displaystyle \sf{cos \bigg( \frac{\pi}{2} - {sin}^{ - 1} \frac{1}{2} \bigg) }$

Step 2 of 2 :

Find the principal value of the expression

$\displaystyle \sf{cos \bigg( \frac{\pi}{2} - {sin}^{ - 1} \frac{1}{2} \bigg) }$

$\displaystyle \sf{ = sin\bigg( {sin}^{ - 1} \frac{1}{2} \bigg) }$

$\displaystyle \sf{ = \frac{1}{2} }$

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ tan⁻¹2 +tan⁻¹3 is

https://brainly.in/question/5596487

2. tan⁻¹(x/y)-tan⁻¹(x-y/x+y)=

https://brainly.in/question/5596504