The principal wants to arrange 5 students on the platform such that the boy ABDUL occupies the 2nd position and the girl DIYA is always adjacent to MANALI. How many such arrangements are possible?
Answers
Answer:
No of ways that Arushi occupies second position = 2C1 = 2
(Position from left and from right)
_ (ARUSHI) _ _ _
Now there are 4 positions left
Out of these 3 positions
When Anubhav 2nd position, Abhishek occupies a place adjacent to him in 2 different ways
When anubhav occupies first place, then Abhishek occupies in 1 way
When anubhav occupies third place, then Abhishek occupies in 1 way
•°• No. of ways Anubhav can occupy a place adjacent to Abhishek is always adjacent to him = 2 + 1 + 1 = 4
The remaining Students occupy a place on remaining two positions in 2 different ways
Hence total Possible ways of Arrangements = 2 × 4 × 2 = 16
Step-by-step explanation:
Answer: 8
Step-by-step explanation:
2nd spot is fixed, and so DIYA and MANALI can only come in the 3-4-5 spaces. (They can't definitely come in 1st position since they have to be side by side and Abdul ha already occupied 2nd position but within them they can interchange.)
So, we can see in how many different ways can Diya and Manali sit.
Other 2 students are marked as numbers while Abdul, Diya and Manlai are symbolized with their first letters.
1 A D M 2
1 A M D 2
1 A 2 M D
1 A 2 D M
So, Diya and Manali can sit in 4 different ways.
After doing this we are left with 2 children and 2 spots, they can also interchange their position. So 2 x 2 = 4
thus 4 + 4 = 8
Hope it was understandable.
If my answer was clear please mark me as brainliest.