The printed price of a computer is ₹ 22000. A dealer allows two successive discounts of 20% and 10%. Find the price which a customer has to pay for the computer.
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Answers
Answered by
0
Step-by-step explanation:
The market price of the computer is Rs 22000
After 10% discount, its cost be
= Rs [22000 - (22000 × 10%)]
= Rs [22000 - (22000 × 10/100)]
= Rs (22000 - 2200)
= Rs 19800
Let us take the cost price of the computer be Rs x
The dealer made a profit of 20%
Then, its selling price was
= Rs [x + (x × 20%)]
= Rs [x + (x × 20/100)]
= Rs (x + x/5)
= Rs (6x/5)
By the given condition,
6x/5 = 19800
→ x = 19800 × 5/6
→ x = 16500
∴ the cost price of the.computer is Rs 16500
Answered by
137
Step-by-step explanation:
We know, for two successive discounts
The marked price of a Computer is 22000
Two successive discount of 20% and 10%
S.P=
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