Math, asked by rajpavit52, 1 month ago

The printed price of a computer is ₹ 22000. A dealer allows two successive discounts of 20% and 10%. Find the price which a customer has to pay for the computer.
I need step by step explanation
fast please​

Answers

Answered by Anonymous
0

Step-by-step explanation:

The market price of the computer is Rs 22000

After 10% discount, its cost be

= Rs [22000 - (22000 × 10%)]

= Rs [22000 - (22000 × 10/100)]

= Rs (22000 - 2200)

= Rs 19800

Let us take the cost price of the computer be Rs x

The dealer made a profit of 20%

Then, its selling price was

= Rs [x + (x × 20%)]

= Rs [x + (x × 20/100)]

= Rs (x + x/5)

= Rs (6x/5)

By the given condition,

6x/5 = 19800

→ x = 19800 × 5/6

→ x = 16500

∴ the cost price of the.computer is Rs 16500

Answered by Anonymous
137

 \fbox \color{black} Answer:-

Step-by-step explanation:

We know, for two successive discounts

s.p = (1 -  \frac{r_{1} }{100} ) \times (1 -  \frac{r  _2  }{100} ) \times m.p

The marked price of a Computer is 22000

Two successive discount of 20% and 10%

S.P=

(1 -  \frac{20}{100} ) \times (1 -  \frac{10}{100}) \times 22000

( \frac{80}{100}) \times ( \frac{90}{100}) \times 22000

8 \times 90 \times 22 = 15,840

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