Question

The probability e of getting a prime number in single throw of a dice is

Zero

1/3

1/2

1/4

​

Answer 1

Answer:

$\huge\bold{\purple{\fbox {\pink{\mathbb{ANSWER}}}}}$

$\bold{\longmapsto}$1, 3 and 5 are prime numbers. The probability of a die coming up a prime numbers is equal to the number of prime numbers (Nprime = 3) divided by the total number of possible results (Ntotal = 6). Thus, p(prime number when tossing one die) = 3/6 = 0.5.

So 1/2 is your correct answer.

$\bold{\purple{\fbox {\green{Hope\:it\:helps\:you}}}}$

$\bold{\purple{\fbox {\orange{Plz\:mark\:as\:brainliest}}}}$

Answer 2

1/2

Step-by-step explanation:

if we throw dice once outcomes are 1,2,3,4,5,6

prime numbers are 2,3 and 5

probability is 3/6=1/2

Hope it helps

please mark it as brainliest.