Question

The probability not getting a sum 11 in a single throw with a pair of dice is
(a) :- 17/18
(b) :- 1/8
(C) :- 7/18
(d) :- 5/6 ​

Answer 1

Answer:

17/18 is the correct answer

Answer 2

$If \:we \: throw \:a \:pair \: of \: dice \:then \\the \: number \: of \: total \: possible \: outcomes = 36\:--(1)$

$Number \: of \: favourable \:outcomes = 34 \: -- ( 2 )$

$\blue{ [Other \:than \: ( 5,6) , (6,5)]}$

$Probability \: of \: not \: getting \:a \: sum \\11 \: in \: a \: single \: throw = \frac{(2)}{(1)} \\= \frac{34}{36} \\= \frac{17}{18}$

Therefore.,

$Option \: \green { ( a ) } \: is \: correct.$

•••♪