Question

the probability not getting a sum 2 in a single throw with a pair of dice ​

Answer 1

Answer:

7/36

Step-by-step explanation:

Total number of outcomes is 36.

Let E be the event of getting the sum as perfect square.

Number of outcomes favourable to E are 7:

(1,3),(2,2),(3,1),(3,6),(4,5),(5,4),(6,3)

Probability of E is number of outcomes favourable to E divided by total number of outcomes that is

36

7

.

Hence, the probability of getting the sum as perfect square is

36

7

.

Answer 2

Step-by-step explanation:

In two throws of a dice, n(S) = (6 x 6) = 36. Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}. P(E) =n(E)/n(S)=4/36=1/9.